Smooth isometric immersions of surfaces into ℝ4
Proves that every closed smooth curved surface can be placed in four-dimensional space with all its distances kept.
A curved surface carries its own rule for measuring lengths, called a metric. An isometric immersion places the surface in flat space so that every length along it is kept, though the surface may pass through itself. Nash's general theorem needs 17 dimensions for surfaces, and Gromov reached five for closed ones. This paper proves that four dimensions always suffice for closed surfaces, and Lean checks the theorem.
The explanation
Take a flat torus, the surface you get by gluing opposite edges of a square without stretching. Give each side length 2π, about 6.283. The map that sends (x, y) to (cos x, sin x, cos y, sin y) places it in four-dimensional space. Moving in x traces a circle of radius 1 in the first two coordinates, at unit speed. Moving in y does the same in the last two. The two directions stay at right angles. So every length on the square is kept exactly. In ordinary three-dimensional space this is impossible for a flat closed surface. Any closed surface there has a point that curves like a sphere.
A closed surface is a finite surface with no edge, like a sphere or a torus. A Riemannian metric is a smooth rule for measuring lengths and angles on it. An isometric immersion is a smooth map into flat space that keeps every such length. Unlike an embedding, it may let the surface pass through itselfSource 1. The question is which dimension is always enough. Gromov recorded the four-dimensional question for surfacesSource 2. He later traced it back to Chern around 1950. Nash's theorem works in dimension 17 for surfaces, since 2 × (3 × 2 + 11)/2 = 17Source 3. Gromov later reached five dimensions for closed surfaces. Poznyak handled four dimensions, but only on flat planar regionsSource 4.
The paper proves that four dimensions sufficeSource 5. Every closed smooth Riemannian surface has a smooth isometric immersion into four-space. No curvature limit is assumed, and surfaces with no consistent sides, like the Klein bottle, are includedSource 6. This lowers the known dimension for closed surfaces from five to fourSource 7.
The proof has four stagesSource 8. It starts with a small map into a round three-dimensional sphere inside four-space, with lengths a bit too short. The missing length is split into finitely many simple pieces on small disks. Each piece is added by a fast circular wiggle in a direction at right angles to the surface. Small further corrections then make the lengths exact. The obstacle is keeping the bending of the surface usable for the next disk. The bending could vanish after one wiggle. The paper tracks it carefully through each step. Its exact correction needs no global inverse of the linearised equationSource 9.
How sure is this? Lean, a computer proof checker, has a formal statement of the main theorem. It covers every closed smooth Riemannian surface, with no orientability assumption. So the paper proves this, as far as the Lean statement matches the paper. No specialist review is published.
What it doesn't show. This does not give an embedding without self-intersections, and it does not cover three-dimensional space.
Where it came from
This result comes from an unreleased OpenAI model, published in the openai/math release on 6 October 2026.
Hype check
A classical question settled for closed surfaces, with a Lean check. It allows self-intersections and says nothing about three-dimensional space. No specialist review is published.
Words used
- Closed surface
- A finite two-dimensional surface with no edge, such as a sphere or a torus.
- Riemannian metric
- A smooth rule for measuring lengths and angles on a surface.
- Isometric immersion
- A smooth map into flat space that keeps every length on the surface; it may pass through itself.
- Embedding
- A placement in space with no self-intersections.
- Nonorientable
- A surface with no consistent choice of two sides, such as the Klein bottle.
- Flat torus
- The surface made by gluing opposite edges of a square with no stretching.
The original paper
All quoted lines (9)
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The result concerns immersion; self-intersections are allowed. There is no restriction on Gaussian curvature or on the topology of the closed surface.
Smooth isometric immersions of closed surfaces into Euclidean four-space Back to text -
Gromov explicitly recorded the question of smooth isometric immersion of arbitrary smooth Riemannian surfaces into .
Smooth isometric immersions of closed surfaces into Euclidean four-space Back to text -
Nash's smooth embedding theorem gives a global realization of a compact -dimensional Riemannian manifold in dimension , which is for surfaces.
Smooth isometric immersions of closed surfaces into Euclidean four-space Back to text -
Poznyak proved that data admit isometric immersions into on compact portions of a simply connected planar domain with regular boundary.
Smooth isometric immersions of closed surfaces into Euclidean four-space Back to text -
Every closed smooth Riemannian surface admits a smooth isometric immersion into Euclidean four-space, without an orientability assumption. This resolves the closed-surface form of the classical four-dimensional isometric-immersion problem.
Smooth isometric immersions of closed surfaces into Euclidean four-space Back to text -
In particular, the construction applies directly to nonorientable surfaces.
Smooth isometric immersions of closed surfaces into Euclidean four-space Back to text -
Theorem … lowers this immersion dimension to four.
Smooth isometric immersions of closed surfaces into Euclidean four-space Back to text -
The proof has four stages. First prepare a smooth immersion into a small round three-sphere in together with a finite decomposition of its metric deficit.
Smooth isometric immersions of closed surfaces into Euclidean four-space Back to text -
No global inverse of the linearized metric map is required.
Smooth isometric immersions of closed surfaces into Euclidean four-space Back to text
Other sources
- openai/math, Lean scope note for family 333
The formalization proves that every closed smooth Riemannian surface admits a smooth isometric immersion into .
- openai/math release notes (2026): model provenance and review status
manuscripts and supporting proof artifacts produced by an internal OpenAI model
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