# Counterexamples to Baum–Connes and Kadison–Kaplansky

> Claims torsion-free groups that break the Kadison–Kaplansky projection conjecture and reduced Baum–Connes. Plain-English explainer with sources.

Canonical: https://closedform.nishachay.tech/e/openai-math-2026-285/
Last updated: 2026-10-14

**Claims torsion-free groups that break the Kadison–Kaplansky projection conjecture and reduced Baum–Connes.**

**Trust:** Claimed, not checked · **Papers:** 3 · **First paper:** September 23, 2026 · **Field:** Operator algebras · **Entry:** 285

*Explained by AI.* Drafted by one AI model and checked sentence by sentence against the paper by a different one. Spot a mistake? Report an error.

To each group one can attach an algebra of operators, the reduced group C*-algebra. Two famous conjectures predict what this algebra looks like for well-behaved groups. Three companion papers claim to build groups where these predictions fail. One group has no elements of finite order, yet its algebra holds a projection other than 0 and 1. Another group's algebra holds a projection whose trace is irrational, which the Baum–Connes conjecture forbids.

## At a glance

- **First step:** 1982 (Paul Baum and Alain Connes, manuscript formulating the conjecture)
- **Significance:** Landmark. Baum–Connes and Kadison–Kaplansky are central conjectures linking group geometry and operator algebras; counterexamples would reshape the field.
- **Trust:** Claimed, not checked
- **Field:** Operator algebras (3 papers)

## The explanation

Start with a group that has two elements, 1 and g, where g times g is 1. Build formal sums a·1 + b·g with complex numbers a and b. Now take e = (1 + g)/2. Squaring gives (1 + 2g + g²)/4 = (2 + 2g)/4, which is e again. An element equal to its own square is a projection. The trace of a sum is its coefficient on 1, so e has trace 1/2. This projection exists because g has finite order. An element of finite order other than 1 is called torsion.

Torsion-free groups seem to behave differently. Take the integers under addition. Their operator algebra turns out to be the continuous functions on a circle. A projection is then a function taking only the values 0 and 1. On a connected circle, such a function must be constant. So the only projections are 0 and 1.

The Kadison–Kaplansky conjecture says this holds for every torsion-free group. The algebra is the reduced group C*-algebra, the closure of the group's sums acting on square-summable sequences. Pimsner and Voiculescu proved the conjecture for free groups[1]. A main route to it is the Baum–Connes conjecture. That conjecture says an assembly map, from the group's topology to the algebra's K-theory, is an isomorphism[2]. K-theory sorts projections into classes. Baum and Connes circulated it in 1982 and published it in 2000[3]. It is known for large classes of groups, including all countable amenable groups[4]. Earlier counterexamples of Higson, Lafforgue and Skandalis used extra coefficients. They do not break the coefficient-free form[5]. The obstacle was to find a group, with no coefficients, whose algebra escapes the topology.

The three papers claim to do that. The first builds a finitely generated torsion-free group whose assembly map sends a class of infinite order to zero[6]. The group is finitely generated, but finite presentation is not part of the conclusion[7]. It disproves neither maximal rational injectivity nor the classical Novikov conjecture[8]. The second builds a finitely generated torsion-free group with a projection other than 0 and the identity[9]. Its trace lies strictly between 0 and 1/2. That projection is in the completed algebra, not in the group ring of finite sums[10]. The third uses Lück's theorem: every assembly class has a rational trace[11]. It then builds a finitely generated group with a projection of irrational trace[12]. That projection cannot come from assembly. The constructions use expander graphs, sparse networks that are still very well connected.

How sure is this? A computer proof checker called Lean has not checked any part of it. Each claim rests on a long chain of graph, spectral and operator estimates. No specialist review of the papers has been published.

**What it doesn't show.** This does not disprove the classical Novikov conjecture or maximal rational injectivity, and it gives no finitely presented example.

## Where it came from

This result comes from an unreleased OpenAI model, published in the openai/math release on 6 October 2026.

## Hype check

Landmark if it holds: these are counterexamples to two central conjectures. There is no Lean check and no published specialist review, so the claims are unconfirmed.

## Words used

- **Torsion-free group:** A group in which no element other than the identity returns to the identity after finitely many repeats.
- **Projection:** An element of an algebra equal to its own square and to its own adjoint, like e = (1 + g)/2 above.
- **Trace:** Here, the coefficient on the identity element; for the example e it is 1/2.
- **Reduced group C*-algebra:** The algebra of operators made by letting the group act on square-summable sequences and closing up in norm.
- **K-theory:** A way of sorting projections in an algebra into classes that can be added.
- **Assembly map:** A map from topological data about the group to the K-theory of its reduced C*-algebra.
- **Finitely generated:** Every element is a product of finitely many fixed generators and their inverses.
- **Expander graph:** A sparse network of points and links that is still very well connected.

## The original papers (3)

- [A torsion-free counterexample to reduced Baum–Connes injectivity](https://github.com/openai/math/blob/main/preprints/A-Torsion-Free-Counterexample-to-Reduced-Baum-Connes-Injectivity-September-23-2026/paper.pdf) - September 23, 2026
- [A torsion-free counterexample to the Kadison–Kaplansky projection conjecture](https://github.com/openai/math/blob/main/preprints/A-Torsion-Free-Counterexample-to-the-Kadison-Kaplansky-Projection-Conjecture-September-23-2026/paper.pdf) - September 23, 2026
- [An irrational-trace counterexample to reduced Baum–Connes](https://github.com/openai/math/blob/main/preprints/An-Irrational-Trace-Counterexample-to-Reduced-Baum-Connes-September-23-2026/paper.pdf) - September 23, 2026

## Quoted lines from the paper (12)

[1] From [A torsion-free counterexample to the Kadison–Kaplansky projection conjecture](https://github.com/openai/math/blob/main/preprints/A-Torsion-Free-Counterexample-to-the-Kadison-Kaplansky-Projection-Conjecture-September-23-2026/paper.pdf):

> Pimsner and Voiculescu proved the free-group case by computing the \(K\)-theory of reduced crossed products by free groups.

[2] From [A torsion-free counterexample to reduced Baum–Connes injectivity](https://github.com/openai/math/blob/main/preprints/A-Torsion-Free-Counterexample-to-Reduced-Baum-Connes-Injectivity-September-23-2026/paper.pdf):

> The Baum--Connes conjecture asserts that this map is an isomorphism.

[3] From [A torsion-free counterexample to reduced Baum–Connes injectivity](https://github.com/openai/math/blob/main/preprints/A-Torsion-Free-Counterexample-to-Reduced-Baum-Connes-Injectivity-September-23-2026/paper.pdf):

> Baum and Connes introduced this index-theoretic comparison in a preprint circulated in 1982 and published in 2000.

[4] From [A torsion-free counterexample to reduced Baum–Connes injectivity](https://github.com/openai/math/blob/main/preprints/A-Torsion-Free-Counterexample-to-Reduced-Baum-Connes-Injectivity-September-23-2026/paper.pdf):

> Higson and Kasparov prove it with separable coefficients for groups acting properly by affine isometries on Hilbert space, including countable amenable groups.

[5] From [An irrational-trace counterexample to reduced Baum–Connes](https://github.com/openai/math/blob/main/preprints/An-Irrational-Trace-Counterexample-to-Reduced-Baum-Connes-September-23-2026/paper.pdf):

> Those constructions do not give a counterexample to the coefficient-free group assertion above.

[6] From [A torsion-free counterexample to reduced Baum–Connes injectivity](https://github.com/openai/math/blob/main/preprints/A-Torsion-Free-Counterexample-to-Reduced-Baum-Connes-Injectivity-September-23-2026/paper.pdf):

> Specifically, we construct a finitely generated torsion-free discrete group whose degree-zero assembly map has a kernel class of infinite order.

[7] From [A torsion-free counterexample to reduced Baum–Connes injectivity](https://github.com/openai/math/blob/main/preprints/A-Torsion-Free-Counterexample-to-Reduced-Baum-Connes-Injectivity-September-23-2026/paper.pdf):

> The group is finitely generated; finite presentation is not part of the conclusion.

[8] From [A torsion-free counterexample to reduced Baum–Connes injectivity](https://github.com/openai/math/blob/main/preprints/A-Torsion-Free-Counterexample-to-Reduced-Baum-Connes-Injectivity-September-23-2026/paper.pdf):

> Our result disproves neither maximal rational injectivity nor this classical assertion; in particular, higher signatures associated to low-degree cohomology already have the homotopy invariance established in.

[9] From [A torsion-free counterexample to the Kadison–Kaplansky projection conjecture](https://github.com/openai/math/blob/main/preprints/A-Torsion-Free-Counterexample-to-the-Kadison-Kaplansky-Projection-Conjecture-September-23-2026/paper.pdf):

> Theorem … resolves the projection form of the Kadison--Kaplansky conjecture negatively.

[10] From [A torsion-free counterexample to the Kadison–Kaplansky projection conjecture](https://github.com/openai/math/blob/main/preprints/A-Torsion-Free-Counterexample-to-the-Kadison-Kaplansky-Projection-Conjecture-September-23-2026/paper.pdf):

> Thus the projection \(e\) lies in the reduced completion but not in the group ring.

[11] From [An irrational-trace counterexample to reduced Baum–Connes](https://github.com/openai/math/blob/main/preprints/An-Irrational-Trace-Counterexample-to-Reduced-Baum-Connes-September-23-2026/paper.pdf):

> L\"uck's trace theorem implies that its value on every degree-zero assembly class is rational.

[12] From [An irrational-trace counterexample to reduced Baum–Connes](https://github.com/openai/math/blob/main/preprints/An-Irrational-Trace-Counterexample-to-Reduced-Baum-Connes-September-23-2026/paper.pdf):

> There exist a finitely generated discrete group \(\Gsur\) and a projection \(b_0\in C_r^*(\Gsur)\) with irrational canonical trace.

## Other sources

- [openai/math release notes (2026): model provenance and review status](https://github.com/openai/math/blob/main/README.md): “manuscripts and supporting proof artifacts produced by an internal OpenAI model”

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